Report: Pacers make sign-and-trade deal with Bucks for Malcolm Brogdon

Milwaukee Bucks guard Malcolm Brogdon, left, drives to the net past Denver Nuggets guard Emmanuel Mudiay, center, and forward Wilson Chandler in the first half of an NBA basketball game Friday, Feb. 3, 2017. (David Zalubowski/AP)

Steven Loung June 30, 2019, 6:44 PM

The Indiana Pacers have acquired guard Malcolm Brogdon from the Milwaukee Bucks and plan to sign him to a four-year, $85-million contract, ESPN’s Adrian Wojnarowski is reporting.

Coming back Milwaukee’s way will be a first-round pick and a couple of future second-round picks.

Indiana is trading a first-round and two future second round picks to the Milwaukee for Malcolm Brogdon, league sources tell ESPN.

— Adrian Wojnarowski (@wojespn) June 30, 2019

Malcolm Brogdon has agreed to a four-year, $85M deal with Indiana, league sources tell ESPN.

— Adrian Wojnarowski (@wojespn) June 30, 2019

Brogon was a restricted free agent, so it would seem the offer Indiana was coming down with was outside of the Bucks’ comfort level, leading to both sides agreeing to a sign-and-trade.

Brogdon was the 2017 NBA Rookie of the Year despite being a second-round pick. The 26-year-old enjoyed a career-year last season with Milwaukee, averaging 15.6 points per game and became just the eighth player to have a 50-40-90 season, shooting 50.5 per cent from the field, 42.6 per cent from three-point range and 92.8 per cent from the free-throw line.

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