Oklahoma City’s Shai Gilgeous-Alexander, Denver’s Nikola Jokic and Milwaukee’s Giannis Antetokounmpo were the only players to appear on every MVP ballot this season.
It only made sense that they would be unanimous All-NBA picks as well.
Gilgeous-Alexander — the league’s MVP — along with Jokic and Antetokounmpo, were unveiled Friday night as first-team All-NBA players, along with Boston’s Jayson Tatum and Cleveland’s Donovan Mitchell.
With his third nod, the Hamilton native Gilgeous-Alexander tied Steve Nash for the most first-team nods for Canadian players.
Tatum was another unanimous first-team pick. Mitchell made the first team for the first time.
Antetokounmpo has seven first-team selections and nine appearances on the All-NBA team overall. Jokic is a five-time first-teamer and seven-time All-NBA pick, Tatum is first-team for the fourth time (fifth overall), Gilgeous-Alexander has been first-team in all three of his All-NBA appearances, and Mitchell is All-NBA for the second time in his career.
Gilgeous-Alexander, Jokic, Antetokounmpo and Tatum were all first-teamers last season as well.
Here's a list of the full All-NBA selections:
First Team
— Shai Gilgeous-Alexander, Oklahoma City Thunder (3x All-NBA)
— Donovan Mitchell, Cleveland Cavaliers (2x All-NBA)
— Jayson Tatum, Boston Celtics (5x All-NBA)
— Giannis Antetokounmpo, Milwaukee Bucks (9x All-NBA)
— Nikola Jokic, Denver Nuggets (7x All-NBA)
Second Team
— Jalen Brunson, New York Knicks (2x All-NBA)
— Anthony Edwards, Minnesota Timberwolves (2x All-NBA)
— Steph Curry, Golden State Warriors (11x All-NBA)
— LeBron James, Los Angeles Lakers (21x All-NBA)
— Evan Mobley, Cleveland Cavaliers (1x All-NBA)
Third team
— Cade Cunningham, Detroit Pistons (1x All-NBA)
— Tyrese Haliburton, Indiana Pacers (2x All-NBA)
— James Harden, Los Angeles Clippers (8x All-NBA)
— Karl-Anthony Towns, New York Knicks (3x All-NBA)
— Jalen Williams, Oklahoma City Thunder (1x All-NBA)
-- With files from Sportsnet Staff
